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Baseball Primer Newsblog— The Best News Links from the Baseball Newsstand
Thursday, October 15, 2009
Yet one unlucky Nats fan told Washington Post sports blogger Dan Steinberg he went to 19 home games, and saw the Nats lose all 19 games. What are the chances? The fan, Stephen Krupin, consulted with mathematician friends, and they came up with a probability of one in 131,204. That’s a reasonable estimate, according to several mathematicians I consulted.
Here’s how to arrive at the estimate. Look back on the Nats schedule and figure that Krupin could have chosen any game as his first to attend. That game would have had a chance of 48/81 of being a loss. His next choice, though, would have a lower chance of 47/80, because one loss was taken. The third’s probability of being a loss would be 46/79, and so on. Multiply those probabilities for all 19 games and you arrive at one in 131,204.
There are other ways to look at it. Suppose that the Nats had a 40.7% chance of winning any given home game. Then the probability of seeing 19 straight losses would be 48/81 to the 19th power, or one in 20,800. Or suppose that the Nats’ 33-29 performance in the 62 games Krupin missed was truly indicative of the team’s quality. Then the probability was an infinitesimal one in 1.86 million.
Which, oddly enough, is the same odds as catching a Frank Coggins HR ball.
Repoz
Posted: October 15, 2009 at 12:19 PM | 24 comment(s)
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Among commenters? One in five. :-(
Hmmm...but he wasn't at the road games, either...
But, on the plus side, it will enhance their chances of landing the hotshot junior high SI coverboy who's skipping high school to enter the draft.
After a Nats game last year I met a guy on the subway who had season tickets and claimed to have gone to something like 150 Nats games since they had been in Washington. I'm not sure whether he was extremely devoted, had nothing going on in his life, or was just crazy. I'm guessing when the Nats start winning it will make it all that sweeter for him.
That man is more devoted than any fan in New York, Boston, Chicago or St. Louis.
Or he is slowly committing suicide.
One of the two.
Of course, they pay me.
I'm praying they don't have children. ::waits for standard BBTF retort should they have them::
Did he, by chance, convey an irrationally exuberant and perhaps icky devotion to the mascot "Screech"?
I suggest they see if there is any way of repressing all memories that do not involve Ryan Zimmerman or Racing Presidents.
Jokes aside, let's say there's 10,000 fans who attended 19 games this year. The chances of this guy going 0-19 might be 1 in 131,000. But the chance of any one of those 10,000 fans going 0-19 would be (roughly) 10,000 in 131,000, or around 7.6%. But the news only notices the one fan that does go 0-19 and we never hear anything about the other 9,999. A chance of 7.6% that it's going to happen to somebody is certainly in the "unlikely but possible" stratum.
you say "jokes aside", but then the rest of that very sentence is a joke. You think there are 10000 people that attended 19+ Nats games this year?
It's the finite population approach. It's essentially answering the question "what are the odds that a random sample (without replacement) of 19 of the Nats' 81 home games in 2009 would be losses?" It's your standard probability problem with a bag with 48 blue balls and 33 red ones.
The other approach is the superpopulation approach -- assume win/lose is a random variable with a known mean and distribution and treat his 19 games as a random draw from that population.
#17 makes a valid point.
And also missed is whether his 19 games were actually a random sample. Probably not. Weekend vs. non-weekend games probably doesn't matter but if he was more likely to go see them play the Phils or the Dodgers than the Pirates, that would either be a biased sample or require you to change the definition of your population (for either approach).
Come to think of it, the Yankees always win when I watch them in Texas now, too.
This is what happens when you let him return.
It's still true that the odds of finding one person who went to a crazy number of losses is a lot higher than the article implies, but I do think it's a lot less likely than one in 12 or 13.
Even crazier, suppose that their performance in the 33 games they won at home was the true indicator of their quality!
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