Engineering

Mechanical EngineeringQ&A LibraryTo use the principle of linear impulse and momentum to relate a force on an object to the resulting velocity of the object at different times. The equation of motion for a particle of mass m can be written as ∑F=ma=mdvdt By rearranging the terms and integrating, this equation becomes the principle of linear impulse and momentum: ∑∫t2t1Fdt=m∫v2v1dv=mv2−mv1 For problem-solving purposes, this principle is often rewritten as mv1+∑∫t2t1Fdt=mv2 The integral ∫Fdt is called the linear impulse, I, and the vector mv is called the particle's linear momentum. A jetliner of mass 8.60×104 kg is in level flight when it encounters a downdraft (a downward wind) that lasts for 1.40 s . The vertical component of the jetliner's velocity is 74.0 m/s after the downdraft subsides. What is the downdraft's average force, F, on the jetliner?Start your trial now! First week only $4.99!*arrow_forward*

Question

To use the principle of linear impulse and momentum to relate a force on an object to the resulting velocity of the object at different times.

The equation of motion for a particle of mass *m*

can be written as

∑**F**=*m***a**=*m**d***v***dt*

By rearranging the terms and integrating, this equation becomes the principle of linear impulse and momentum:

∑∫*t*2*t*1**F***dt*=*m*∫**v**2**v**1*d***v**=*m***v**2−*m***v**1

For problem-solving purposes, this principle is often rewritten as

*m***v**1+∑∫*t*2*t*1**F***dt*=*m***v**2

The integral ∫**F***dt* is called the linear impulse, **I**, and the vector *m***v** is called the particle's linear momentum.

A jetliner of mass 8.60×10^{4} kg is in level flight when it encounters a downdraft (a downward wind) that lasts for 1.40 s . The vertical component of the jetliner's velocity is 74.0 m/s after the downdraft subsides. What is the downdraft's average force, *F*, on the jetliner?

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